max_align_t
From cppreference.com
| Defined in header <stddef.h>
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| typedef /*implementation-defined*/ max_align_t; |
(since C11) | |
max_align_t is a type whose alignment requirement is at least as strict (as large) as that of every scalar type.
[edit] Notes
Pointers returned by allocation functions such as malloc are suitably aligned for any object, which means they are aligned at least as strictly as max_align_t.
max_align_t is usually synonymous with the largest scalar type, which is long double on most platforms, and its alignment requirement is either 8 or 16.
[edit] Example
Run this code
#include <stdio.h> #include <stddef.h> #include <stdalign.h> #include <stdlib.h> #include <stdint.h> #include <inttypes.h> int main(void) { size_t a = alignof(max_align_t); printf("Alignment of max_align_t is %zu (%#zx)\n", a, a); int *p = malloc(123); printf("The address obtained from malloc(123) is %#" PRIxPTR"\n", (uintptr_t)p); free(p); }
Possible output:
Alignment of max_align_t is 16 (0x10) The address obtained from malloc(123) is 0x1fa67010
[edit] See also
| C++ documentation for max_align_t
|
